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2019-05-17
:
def mark_trip_as_featured(trip):
"""将某个旅程添加到推荐栏目
"""
if trip.source == 11:
do_some_thing(trip)
elif trip.source == 12:
do_some_other_thing(trip)
... ...
return
# -*- coding: utf-8 -*-
from enum import IntEnum
class TripSource(IntEnum):
FROM_WEBSITE = 11
FROM_IOS_CLIENT = 12
def mark_trip_as_featured(trip):
if trip.source == TripSource.FROM_WEBSITE:
do_some_thing(trip)
elif trip.source == TripSource.FROM_IOS_CLIENT:
do_some_other_thing(trip)
... ...
return
def fetch_users(conn, min_level=None, gender=None, has_membership=False, sort_field="created"):
"""获取用户列表
:param int min_level: 要求的最低用户级别,默认为所有级别
:param int gender: 筛选用户性别,默认为所有性别
:param int has_membership: 筛选所有会员/非会员用户,默认非会员
:param str sort_field: 排序字段,默认为按 created "用户创建日期"
:returns: 列表:[(User ID, User Name), ...]
"""
# 一种古老的 SQL 拼接技巧,使用 "WHERE 1=1" 来简化字符串拼接操作
# 区分查询 params 来避免 SQL 注入问题
statement = "SELECT id, name FROM users WHERE 1=1"
params = []
if min_level is not None:
statement += " AND level >= ?"
params.append(min_level)
if gender is not None:
statement += " AND gender >= ?"
params.append(gender)
if has_membership:
statement += " AND has_membership == true"
else:
statement += " AND has_membership == false"
statement += " ORDER BY ?"
params.append(sort_field)
return list(conn.execute(statement, params))
def fetch_users_v2(conn, min_level=None, gender=None, has_membership=False, sort_field="created"):
"""获取用户列表
"""
query = select([users.c.id, users.c.name])
if min_level is not None:
query = query.where(users.c.level >= min_level)
if gender is not None:
query = query.where(users.c.gender == gender)
query = query.where(users.c.has_membership == has_membership).order_by(users.c[sort_field])
return list(conn.execute(query))
def f1(delta_seconds):
# 如果时间已经过去了超过 11 天,不做任何事
if delta_seconds > 950400:
return
...
def f1(delta_seconds):
if delta_seconds < 11 * 24 * 3600:
return
import dis
dis.dis(f1)
# dis 执行结果
5 0 LOAD_FAST 0 (delta_seconds)
2 LOAD_CONST 1 (950400)
4 COMPARE_OP 0 (<)
6 POP_JUMP_IF_FALSE 12
6 8 LOAD_CONST 0 (None)
10 RETURN_VALUE
>> 12 LOAD_CONST 0 (None)
14 RETURN_VALU
>>> True + 1
2
>>> 1 / False
Traceback (most recent call last):
File "<stdin>", line 1, in <module>
ZeroDivisionError: division by zero
>>> l = [1, 2, 4, 5, 7]
>>> sum(i % 2 == 0 for i in l)
2
# 类似的三元表达式:"Javascript" if 2 > 1 else "Python"
>>> ["Python", "Javascript"][2 > 1]
'Javascript'
def main():
logger.info(("There is something really bad happened during the process. "
"Please contact your administrator."))
def main():
if user.is_active:
message = """Welcome, today's movie list:
- Jaw (1975)
- The Shining (1980)
- Saw (2004)""
from textwrap import dedent
def main():
if user.is_active:
# dedent 将会缩进掉整段文字最左边的空字符串
message = dedent("""\
Welcome, today's movie list:
- Jaw (1975)
- The Shining (1980)
- Saw (2004)""")
>>> log_line = '"AppleWebKit/537.36 (KHTML, like Gecko) Chrome/70.0.3538.77 Safari/537.36" 47632'
如果使用 .split() 将日志拆分为 (user_agent, content_length) ,我们需要这么写:
>>> l = log_line.split()
>>> " ".join(l[:-1]), l[-1]
('"AppleWebKit/537.36 (KHTML, like Gecko) Chrome/70.0.3538.77 Safari/537.36"', '47632')
但是如果使用 .rsplit() 的话,处理逻辑就更直接了:
>>> log_line.rsplit(None, 1)
['"AppleWebKit/537.36 (KHTML, like Gecko) Chrome/70.0.3538.77 Safari/537.36"', '47632']
:
# A. 根据年龄升序排序,没有提供年龄放在最后边
>>> users = {"tom": 19, "jenny": 13, "jack": None, "andrew": 43}
>>> sorted(users.keys(), key=lambda user: users.get(user) or float('inf'))
['jenny', 'tom', 'andrew', 'jack']
# B. 作为循环初始值,简化第一次判断逻辑
>>> max_num = float('-inf')
>>> # 找到列表中最大的数字
>>> for i in [23, 71, 3, 21, 8]:
...: if i > max_num:
...: max_num = i
...:
>>> max_num
71
def incr(value):
value += 1
# 使用 dis 模块查看字节码
import dis
dis.dis(incr)
0 LOAD_FAST 0 (value)
2 LOAD_CONST 1 (1)
4 INPLACE_ADD
6 STORE_FAST 0 (value)
8 LOAD_CONST 0 (None)
10 RETURN_VALUE
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